0=90+4x+12x^2

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Solution for 0=90+4x+12x^2 equation: 



0=90+4x+12x^2

We move all terms to the left:

0-(90+4x+12x^2)=0

We add all the numbers together, and all the variables

-(90+4x+12x^2)=0

We get rid of parentheses

-12x^2-4x-90=0

a = -12; b = -4; c = -90;
Δ = b2-4ac
Δ = -42-4·(-12)·(-90)
Δ = -4304
Delta is less than zero, so there is no solution for the equation

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